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mathsGrade 9-102 min read

Quadratic equations: three methods, and when to use each

Factorising, the quadratic formula, completing the square — they all solve the same equation. The skill is reading the question and knowing which one is fastest here.

A quadratic is any equation that rearranges to

ax2+bx+c=0.ax^2 + bx + c = 0.

There are three standard ways to solve it, and they always give the same answer. Choosing well is the difference between a clean two lines and a page of arithmetic.

Method 1 — Factorising (try this first)

If the quadratic factorises nicely, this is the fastest route. Find two numbers that multiply to acac and add to bb, split the middle term, and factor.

x2+5x+6=0    (x+2)(x+3)=0    x=2 or x=3.x^2 + 5x + 6 = 0 \;\Rightarrow\; (x+2)(x+3) = 0 \;\Rightarrow\; x = -2 \text{ or } x = -3.

The trick: a product equals zero only if one of the brackets is zero. So set each bracket to zero separately.

Method 2 — The quadratic formula (always works)

When factorising won't come, the formula never fails:

x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

The part under the root, b24acb^2 - 4ac, is the discriminant, and it tells you about the roots before you finish:

b24acb^2 - 4acRoots
PositiveTwo different real roots
ZeroOne repeated root
NegativeNo real roots

Method 3 — Completing the square

Slower to solve with, but it's the method that reveals the turning point of the curve, so it earns its keep in graph questions:

x2+6x+1=(x+3)29+1=(x+3)28x^2 + 6x + 1 = (x+3)^2 - 9 + 1 = (x+3)^2 - 8

The minimum sits at (3,8)(-3, -8) — you can read the vertex straight off.

Which to pick

Rearrange to "= 0" first, every time. All three methods assume the quadratic is set equal to zero. The most common lost mark is solving x2+5x=6x^2 + 5x = 6 without first moving the 66 across.

Last revised 28 January 2025.